What is the answer to log_{2}(x+3)+log_{2}(x-1)=5 ?

The answer to log_{2}(x+3)+log_{2}(x-1)=5 is x=5

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log_{2}(x+3)+log_{2}(x-1)=5

lo g_{2} (x + 3) + lo g_{2} (x - 1) = 5

x = 5

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x - 1) = 5

Apply log rules

(x + 3) (x - 1) = 32

Solve

(x + 3) (x - 1) = 32 : x = 5, x = - 7

x = 5, x = - 7

Verify Solutions:

x = 5

True

, x = - 7

False

The solution is

x = 5

ln (x) = 7.5

lo g_{10} (x) + lo g_{10} (x + 1) = 5

lo g_{2} (ln (x)) = 1

lo g_{3} (5 x - 8) = 1

x, ln (x) = 5

What is the answer to log_{2}(x+3)+log_{2}(x-1)=5 ?
The answer to log_{2}(x+3)+log_{2}(x-1)=5 is x=5
Solve for x: log_{2}(x+3)+log_{2}(x-1)=5
The solution is x=5