What is the answer to log_{10}(1+x)=10 ?

The answer to log_{10}(1+x)=10 is x=10^{10}-1

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log_{10}(1+x)=10

lo g_{10} (1 + x) = 10

x = 1 0^{10} - 1

Decimal Notation

x = 9999999999

Solution steps

lo g_{10} (1 + x) = 10

Apply log rules

1 + x = 1 0^{10}

Solve

1 + x = 1 0^{10} : x = 1 0^{10} - 1

x = 1 0^{10} - 1

lo g_{b} (\frac{1}{16}) = - 2

4 = ln (x)

2 lo g_{4} (x - 5) + lo g_{4} (4) = 2

lo g_{3} (x + 1) - lo g_{3} (x - 1) = 2

x^{2 l o g_{9} (x) - 1} = 3 x

What is the answer to log_{10}(1+x)=10 ?
The answer to log_{10}(1+x)=10 is x=10^{10}-1
Solve for x: log_{10}(1+x)=10
The solution is x=10^{10}-1