What is the answer to log_{2}(x+3)+log_{2}(x+1)=3 ?

The answer to log_{2}(x+3)+log_{2}(x+1)=3 is x=1

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log_{2}(x+3)+log_{2}(x+1)=3

lo g_{2} (x + 3) + lo g_{2} (x + 1) = 3

x = 1

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x + 1) = 3

Apply log rules

(x + 3) (x + 1) = 8

Solve

(x + 3) (x + 1) = 8 : x = 1, x = - 5

x = 1, x = - 5

Verify Solutions:

x = 1

True

, x = - 5

False

The solution is

x = 1

lo g_{5} (x + 3) + lo g_{5} (2) = 2

x, lo g_{8} (x y) = 3

0.43 = ln (y)

lo g_{\frac{3}{2}} (X) = - 2

lo g_{6} (- x^{2} + 20 x) = 2

What is the answer to log_{2}(x+3)+log_{2}(x+1)=3 ?
The answer to log_{2}(x+3)+log_{2}(x+1)=3 is x=1
Solve for x: log_{2}(x+3)+log_{2}(x+1)=3
The solution is x=1