What is the answer to ln(x)+ln(x-2)=2 ?

The answer to ln(x)+ln(x-2)=2 is x=(2+sqrt(4+4e^2))/2

Solve for x: ln(x)+ln(x-2)=2

The solution is x=(2+sqrt(4+4e^2))/2

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ln (x) + ln (x - 2) = 2

x = \frac{2 + 4 + 4 e ^{2}}{2}

Decimal Notation

x = 3.89638 \dots

Solution steps

ln (x) + ln (x - 2) = 2

Apply log rules

x (x - 2) = e^{2}

Solve

x (x - 2) = e^{2} : x = \frac{2 + 4 + 4 e ^{2}}{2}, x = \frac{2 - 4 + 4 e ^{2}}{2}

x = \frac{2 + 4 + 4 e ^{2}}{2}, x = \frac{2 - 4 + 4 e ^{2}}{2}

Verify Solutions:

x = \frac{2 + 4 + 4 e ^{2}}{2}

True

, x = \frac{2 - 4 + 4 e ^{2}}{2}

False

The solution is

x = \frac{2 + 4 + 4 e ^{2}}{2}

ln (x^{2} + 3) - ln (x^{2}) = 1

ln (x) ln (x) = 1

lo g_{x} (3 x + 4) = lo g_{x} (4 x + 2)

lo g_{4} (x) - lo g_{x} (64) = 2

lo g_{3} (x + 2) + lo g_{3} (3 x) = 2

What is the answer to ln(x)+ln(x-2)=2 ?
The answer to ln(x)+ln(x-2)=2 is x=(2+sqrt(4+4e^2))/2
Solve for x: ln(x)+ln(x-2)=2
The solution is x=(2+sqrt(4+4e^2))/2