What is the answer to log_{x}(2)=x ?

The answer to log_{x}(2)=x is x=(ln(2))/(\W_{0)(ln(2))}

Solve for x: log_{x}(2)=x

The solution is x=(ln(2))/(\W_{0)(ln(2))}

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lo g_{x} (2) = x

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

Decimal Notation

x = 1.55961 \dots

Solution steps

lo g_{x} (2) = x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

x^{l o g_{x} (2)} = x^{x}

Simplify

x^{l o g_{x} (2)} : 2

2 = x^{x}

Solve

2 = x^{x} : x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

Verify Solutions:

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

True

The solution is

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

lo g_{10} (x) = 1.44

lo g_{16} (x) = 2

lo g_{2} (x) = 25

2 - lo g_{3} (x - 4) = lo g_{3} (x - 2)

What is the answer to log_{x}(2)=x ?
The answer to log_{x}(2)=x is x=(ln(2))/(\W_{0)(ln(2))}
Solve for x: log_{x}(2)=x
The solution is x=(ln(2))/(\W_{0)(ln(2))}