What is the answer to log_{10}(x+2)+log_{10}(4)=1 ?

The answer to log_{10}(x+2)+log_{10}(4)=1 is x= 1/2

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log_{10}(x+2)+log_{10}(4)=1

lo g_{10} (x + 2) + lo g_{10} (4) = 1

x = \frac{1}{2}

Solution steps

lo g_{10} (x + 2) + lo g_{10} (4) = 1

Move

lo g_{10} (4)

to the right side

lo g_{10} (x + 2) = 1 - lo g_{10} (4)

Apply log rules

x + 2 = \frac{5}{2}

Solve

x + 2 = \frac{5}{2} : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

7 - ln (3 - x) = 0

ln (x) + x = - 1

x, ln (x^{2}) = 14

lo g_{10} (∣ x ∣) = - 4

(2 x - 1) + ln (x) = 0

What is the answer to log_{10}(x+2)+log_{10}(4)=1 ?
The answer to log_{10}(x+2)+log_{10}(4)=1 is x= 1/2
Solve for x: log_{10}(x+2)+log_{10}(4)=1
The solution is x= 1/2