What is the answer to log_{2}(3x+1)=log_{2}(2x) ?

The answer to log_{2}(3x+1)=log_{2}(2x) is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(3x+1)=log_{2}(2x)

The solution is No Solution for x\in\mathbb{R}

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lo g_{2} (3 x + 1) = lo g_{2} (2 x)

No Solution for x \in R

Solution steps

lo g_{2} (3 x + 1) = lo g_{2} (2 x)

Apply log rules

3 x + 1 = 2 x

Solve

3 x + 1 = 2 x : x = - 1

x = - 1

Verify Solutions:

x = - 1

False

The solution is

No Solution for x \in R

x, lo g_{2} (x + 3) = 5

lo g_{x} (8) = - 2

lo g_{10} (x) + lo g_{10} (30) = 4

lo g_{10} (x) + lo g_{10} (x + 5) = 3

lo g_{10} (x) + lo g_{10} (x + 5) = 1

What is the answer to log_{2}(3x+1)=log_{2}(2x) ?
The answer to log_{2}(3x+1)=log_{2}(2x) is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(3x+1)=log_{2}(2x)
The solution is No Solution for x\in\mathbb{R}