What are the solutions to the equation x^2+2-8=0 ?

The solutions to the equation x^2+2-8=0 are x=sqrt(6),x=-sqrt(6)

Find the zeros of x^2+2-8=0

The zeros of x^2+2-8=0 are x=sqrt(6),x=-sqrt(6)

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x^{2} + 2 - 8 = 0

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

x^{2} + 2 - 8 = 0

Move

2

to the right side

x^{2} - 8 = - 2

Move

8

to the right side

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

120 x^{3} - 80 x^{2} - 168 x + 112

5 - 2 x = 4 + x

5 x^{2} - 38 x + 21

\frac{1}{x - 5} + \frac{1}{x + 2} \geq \frac{2 x}{x ^{2} + x - 2}

6 d + 21 = 75

What are the solutions to the equation x^2+2-8=0 ?
The solutions to the equation x^2+2-8=0 are x=sqrt(6),x=-sqrt(6)
Find the zeros of x^2+2-8=0
The zeros of x^2+2-8=0 are x=sqrt(6),x=-sqrt(6)