What is the answer to ln(x+5)=1+ln(x) ?

The answer to ln(x+5)=1+ln(x) is x= 5/(e-1)

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ln(x+5)=1+ln(x)

ln (x + 5) = 1 + ln (x)

x = \frac{5}{e - 1}

Solution steps

ln (x + 5) = 1 + ln (x)

Apply log rules

x + 5 = e x

Solve

x + 5 = e x : x = \frac{5}{e - 1}

x = \frac{5}{e - 1}

Verify Solutions:

x = \frac{5}{e - 1}

True

The solution is

x = \frac{5}{e - 1}

3 lo g_{3} (x - 2) = 5

lo g_{x - 1} (4) = 2

23 = 10 lo g_{10} (x)

x, f = 1 + lo g_{2} (x + k)

lo g_{2} (N) = - 2

What is the answer to ln(x+5)=1+ln(x) ?
The answer to ln(x+5)=1+ln(x) is x= 5/(e-1)
Solve for x: ln(x+5)=1+ln(x)
The solution is x= 5/(e-1)