What is the answer to 2ln(6x-3)+11=19 ?

The answer to 2ln(6x-3)+11=19 is x=(e^4+3)/6

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2ln(6x-3)+11=19

2 ln (6 x - 3) + 11 = 19

x = \frac{e ^{4} + 3}{6}

Decimal Notation

x = 9.59969 \dots

Solution steps

2 ln (6 x - 3) + 11 = 19

Move

11

to the right side

2 ln (6 x - 3) = 8

Divide both sides by

2

ln (6 x - 3) = 4

Apply log rules

6 x - 3 = e^{4}

Solve

6 x - 3 = e^{4} : x = \frac{e ^{4} + 3}{6}

x = \frac{e ^{4} + 3}{6}

Verify Solutions:

x = \frac{e ^{4} + 3}{6}

True

The solution is

x = \frac{e ^{4} + 3}{6}

lo g_{2} (2) + lo g_{2} (x) = 2

lo g_{b} (2) = - \frac{1}{2}

2 ln (y) = 12

ln (3 x - 17) = 8

ln (3 x - 17) = 3

What is the answer to 2ln(6x-3)+11=19 ?
The answer to 2ln(6x-3)+11=19 is x=(e^4+3)/6
Solve for x: 2ln(6x-3)+11=19
The solution is x=(e^4+3)/6