What is the answer to 0=log_{2}(3x-4)+1 ?

The answer to 0=log_{2}(3x-4)+1 is x= 3/2

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0=log_{2}(3x-4)+1

0 = lo g_{2} (3 x - 4) + 1

x = \frac{3}{2}

Solution steps

0 = lo g_{2} (3 x - 4) + 1

Switch sides

lo g_{2} (3 x - 4) + 1 = 0

Move

1

to the right side

lo g_{2} (3 x - 4) = - 1

Apply log rules

3 x - 4 = \frac{1}{2}

Solve

3 x - 4 = \frac{1}{2} : x = \frac{3}{2}

x = \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

The solution is

x = \frac{3}{2}

ln (2 x) + ln (4 x) = 0

ln (x) = 1 - ln (x - 3)

2 ln (x) - ln (x + 5) = ln (x) - ln (3)

2 ln (x) - ln (x - 1) = ln (4)

3.5 = 1.5 + lo g_{3} (x + 1)

What is the answer to 0=log_{2}(3x-4)+1 ?
The answer to 0=log_{2}(3x-4)+1 is x= 3/2
Solve for x: 0=log_{2}(3x-4)+1
The solution is x= 3/2