What is the answer to 2log_{2}(x+2)-log_{2}(x+1)=2 ?

The answer to 2log_{2}(x+2)-log_{2}(x+1)=2 is x=0

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2log_{2}(x+2)-log_{2}(x+1)=2

2 lo g_{2} (x + 2) - lo g_{2} (x + 1) = 2

x = 0

Solution steps

2 lo g_{2} (x + 2) - lo g_{2} (x + 1) = 2

Apply log rules

(x + 2)^{2} = 4 (x + 1)

Solve

(x + 2)^{2} = 4 (x + 1) : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

lo g_{x} (4) = 4 lo g_{x} (x)

lo g_{3} (x^{2} - 8) = 2

0 = 2 x ln (x) + x

123 = 10 lo g_{10} (\frac{x}{1})

lo g_{2} (x - 10) = 6

What is the answer to 2log_{2}(x+2)-log_{2}(x+1)=2 ?
The answer to 2log_{2}(x+2)-log_{2}(x+1)=2 is x=0
Solve for x: 2log_{2}(x+2)-log_{2}(x+1)=2
The solution is x=0