What is the answer to log_{4}((x+1)^6)=12 ?

The answer to log_{4}((x+1)^6)=12 is x=15,x=-17

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log_{4}((x+1)^6)=12

lo g_{4} ((x + 1)^{6}) = 12

x = 15, x = - 17

Solution steps

lo g_{4} ((x + 1)^{6}) = 12

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

(x + 1)^{6} = ((x + 1)^{2})^{3}

lo g_{4} (((x + 1)^{2})^{3}) = 12

Apply log rules

(x + 1)^{2} = 256

Solve

(x + 1)^{2} = 256 : x = 15, x = - 17

x = 15, x = - 17

Verify Solutions:

x = 15

True

, x = - 17

True

The solutions are

x = 15, x = - 17

lo g_{10} (n) = lo g_{10} (n)

lo g_{5} (x - 2) = 3

- 3 lo g_{11} (x + 4) = - 6

4.7 = 5 - lo g_{10} (\frac{0.5}{x})

lo g_{6} (x) = 5

What is the answer to log_{4}((x+1)^6)=12 ?
The answer to log_{4}((x+1)^6)=12 is x=15,x=-17
Solve for x: log_{4}((x+1)^6)=12
The solution is x=15,x=-17