What is the answer to log_{2x-2}(3x^2-3x-2)=2 ?

The answer to log_{2x-2}(3x^2-3x-2)=2 is x=2,x=3

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log_{2x-2}(3x^2-3x-2)=2

lo g_{2 x - 2} (3 x^{2} - 3 x - 2) = 2

x = 2, x = 3

Solution steps

lo g_{2 x - 2} (3 x^{2} - 3 x - 2) = 2

Apply log rules

\frac{ln ( 3 x ^{2} - 3 x - 2 )}{ln ( 2 x - 2 )} = 2

Multiply both sides by

ln (2 x - 2)

\frac{ln ( 3 x ^{2} - 3 x - 2 )}{ln ( 2 x - 2 )} ln (2 x - 2) = 2 ln (2 x - 2)

Simplify

ln (3 x^{2} - 3 x - 2) = 2 ln (2 x - 2)

Apply log rules

3 x^{2} - 3 x - 2 = (2 x - 2)^{2}

Solve

3 x^{2} - 3 x - 2 = (2 x - 2)^{2} : x = 2, x = 3

x = 2, x = 3

Verify Solutions:

x = 2

True

, x = 3

True

The solutions are

x = 2, x = 3

lo g_{10} (\frac{x}{10}) = 2

5 ln (5 x + 9) - 4 = 11

0.44 = ln (x)

lo g_{10} (x) = \frac{4}{3}

lo g_{3} (2 x) - lo g_{3} (x - 1) = 2

What is the answer to log_{2x-2}(3x^2-3x-2)=2 ?
The answer to log_{2x-2}(3x^2-3x-2)=2 is x=2,x=3
Solve for x: log_{2x-2}(3x^2-3x-2)=2
The solution is x=2,x=3