What is the answer to 3+log_{10}(1-3x)=0 ?

The answer to 3+log_{10}(1-3x)=0 is x= 333/1000

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3+log_{10}(1-3x)=0

3 + lo g_{10} (1 - 3 x) = 0

x = \frac{333}{1000}

Solution steps

3 + lo g_{10} (1 - 3 x) = 0

Move

3

to the right side

lo g_{10} (1 - 3 x) = - 3

Apply log rules

1 - 3 x = \frac{1}{1000}

Solve

1 - 3 x = \frac{1}{1000} : x = \frac{333}{1000}

x = \frac{333}{1000}

Verify Solutions:

x = \frac{333}{1000}

True

The solution is

x = \frac{333}{1000}

lo g_{x} (10) = 3

ln (x) = (\frac{a}{3}) + 1

lo g_{x} (4096) = 6

- ln (- x) = 0

lo g_{2} (x) + 8 = 12

What is the answer to 3+log_{10}(1-3x)=0 ?
The answer to 3+log_{10}(1-3x)=0 is x= 333/1000
Solve for x: 3+log_{10}(1-3x)=0
The solution is x= 333/1000