What is the answer to log_{10}(x)+log_{10}(x-4)=1 ?

The answer to log_{10}(x)+log_{10}(x-4)=1 is x=2+sqrt(14)

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log_{10}(x)+log_{10}(x-4)=1

lo g_{10} (x) + lo g_{10} (x - 4) = 1

x = 2 + 14

Solution steps

lo g_{10} (x) + lo g_{10} (x - 4) = 1

Apply log rules

x (x - 4) = 10

Solve

x (x - 4) = 10 : x = 2 + 14, x = 2 - 14

x = 2 + 14, x = 2 - 14

Verify Solutions:

x = 2 + 14

True

, x = 2 - 14

False

The solution is

x = 2 + 14

ln (x) = 1 - 3 ln (2)

lo g_{8} (x + 30) + lo g_{8} (x) = 2

x, ln (y) = - 3 ln (x)

ln (3 x - 13) = 5

ln (3 x - 13) = 3

What is the answer to log_{10}(x)+log_{10}(x-4)=1 ?
The answer to log_{10}(x)+log_{10}(x-4)=1 is x=2+sqrt(14)
Solve for x: log_{10}(x)+log_{10}(x-4)=1
The solution is x=2+sqrt(14)