What is the answer to 2ln(3x^2)-ln(x)=4 ?

The answer to 2ln(3x^2)-ln(x)=4 is x=e^{(4-2ln(3))/3}

Solve for x: 2ln(3x^2)-ln(x)=4

The solution is x=e^{(4-2ln(3))/3}

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2 ln (3 x^{2}) - ln (x) = 4

x = e^{\frac{4 - 2 l n ( 3 )}{3}}

Solution steps

2 ln (3 x^{2}) - ln (x) = 4

Apply log rules

x = e^{\frac{4 - 2 l n ( 3 )}{3}}

Verify Solutions:

x = e^{\frac{4 - 2 l n ( 3 )}{3}}

True

The solution is

x = e^{\frac{4 - 2 l n ( 3 )}{3}}

y, \frac{1}{2} ln (y) = x

lo g_{10} (x) = - 1.2

- 5 = lo g_{4} (5 x + 9) - 8

5 = ln (x)

- 17 = 5 - lo g_{10} (X) - 15 \cdot X

What is the answer to 2ln(3x^2)-ln(x)=4 ?
The answer to 2ln(3x^2)-ln(x)=4 is x=e^{(4-2ln(3))/3}
Solve for x: 2ln(3x^2)-ln(x)=4
The solution is x=e^{(4-2ln(3))/3}