What is the answer to log_{10}(5x-1)=log_{10}(9x) ?

The answer to log_{10}(5x-1)=log_{10}(9x) is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(5x-1)=log_{10}(9x)

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (5 x - 1) = lo g_{10} (9 x)

No Solution for x \in R

Solution steps

lo g_{10} (5 x - 1) = lo g_{10} (9 x)

Apply log rules

5 x - 1 = 9 x

Solve

5 x - 1 = 9 x : x = - \frac{1}{4}

x = - \frac{1}{4}

Verify Solutions:

x = - \frac{1}{4}

False

The solution is

No Solution for x \in R

lo g_{10} (x) = \frac{3}{2}

x, ln (y) = n ln (x) + c

0.56 = ln (x)

ln (5 x + 3) = 4

lo g_{9} (3^{x + 1}) = x^{2}

What is the answer to log_{10}(5x-1)=log_{10}(9x) ?
The answer to log_{10}(5x-1)=log_{10}(9x) is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(5x-1)=log_{10}(9x)
The solution is No Solution for x\in\mathbb{R}