What is the answer to 5=log_{x}(32) ?

The answer to 5=log_{x}(32) is x=2

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5=log_{x}(32)

5 = lo g_{x} (32)

x = 2

Solution steps

5 = lo g_{x} (32)

Apply log rules

5 = \frac{1}{lo g _{32} ( x )}

Multiply both sides by

lo g_{32} (x)

5 lo g_{32} (x) = \frac{1}{lo g _{32} ( x )} lo g_{32} (x)

Simplify

5 lo g_{32} (x) = 1

Divide both sides by

5

lo g_{32} (x) = \frac{1}{5}

Apply log rules

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{7} (x) = 21

0.9 = ln (y)

lo g_{2} (x + 5) - lo g_{2} (6) = 3

lo g_{10} (x) = 2

25.52 = - lo g_{10} (x)