What is the answer to ln(3x+1)=7.492 ?

The answer to ln(3x+1)=7.492 is x=(e^{7.492}-1)/3

Solve for x: ln(3x+1)=7.492

The solution is x=(e^{7.492}-1)/3

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ln (3 x + 1) = 7.492

x = \frac{e ^{7.492} - 1}{3}

Decimal Notation

x = 597.54525 \dots

Solution steps

ln (3 x + 1) = 7.492

Apply log rules

3 x + 1 = e^{7.492}

Solve

3 x + 1 = e^{7.492} : x = \frac{e ^{7.492} - 1}{3}

x = \frac{e ^{7.492} - 1}{3}

2 + ln (t - 5) = 2.5

- lo g_{10} (x) = 1.3

ln (x) - ln (2 x - 5) = ln (3)

lo g_{2} ((r + 6)^{2}) = 4

ln (y) + ln (y + 3) = ln (20 - 5 y)

What is the answer to ln(3x+1)=7.492 ?
The answer to ln(3x+1)=7.492 is x=(e^{7.492}-1)/3
Solve for x: ln(3x+1)=7.492
The solution is x=(e^{7.492}-1)/3