What are the solutions to the equation (2x+8)^2=27 ?

The solutions to the equation (2x+8)^2=27 are x=(3sqrt(3)-8)/2 ,x=(-3sqrt(3)-8)/2

Find the zeros of (2x+8)^2=27

The zeros of (2x+8)^2=27 are x=(3sqrt(3)-8)/2 ,x=(-3sqrt(3)-8)/2

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(2 x + 8)^{2} = 27

x = \frac{3 3 - 8}{2}, x = \frac{- 3 3 - 8}{2}

Solution steps

(2 x + 8)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 8 = 27 : x = \frac{3 3 - 8}{2}

Solve

2 x + 8 = - 27 : x = \frac{- 3 3 - 8}{2}

The solutions to the quadratic equation are:

x = \frac{3 3 - 8}{2}, x = \frac{- 3 3 - 8}{2}

\frac{1}{3} - \frac{5}{6}

(x - 2)^{2} = (x - 6)^{2}

3 x^{2} - 5 x + 12 = 0

m^{2} + 9 m - 22

\frac{2 7 - 3}{7 - 2}

What are the solutions to the equation (2x+8)^2=27 ?
The solutions to the equation (2x+8)^2=27 are x=(3sqrt(3)-8)/2 ,x=(-3sqrt(3)-8)/2
Find the zeros of (2x+8)^2=27
The zeros of (2x+8)^2=27 are x=(3sqrt(3)-8)/2 ,x=(-3sqrt(3)-8)/2