What is the answer to log_{6}(-x^2+37x)=2 ?

The answer to log_{6}(-x^2+37x)=2 is x=1,x=36

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log_{6}(-x^2+37x)=2

lo g_{6} (- x^{2} + 37 x) = 2

x = 1, x = 36

Solution steps

lo g_{6} (- x^{2} + 37 x) = 2

Apply log rules

- x^{2} + 37 x = 36

Solve

- x^{2} + 37 x = 36 : x = 1, x = 36

x = 1, x = 36

0 = lo g_{10} (\frac{x - 2}{x + 4}) + 2

3 lo g_{x} (81) = - 12

lo g_{a} (x + 1) = 1 + lo g_{a} (x)

lo g_{4} (5 x - 9) - 2 = 0

lo g_{8} (x + 4) = 2

What is the answer to log_{6}(-x^2+37x)=2 ?
The answer to log_{6}(-x^2+37x)=2 is x=1,x=36
Solve for x: log_{6}(-x^2+37x)=2
The solution is x=1,x=36