What is the answer to log_{3}(x-1)+log_{3}(x+2)=1 ?

The answer to log_{3}(x-1)+log_{3}(x+2)=1 is x=(-1+sqrt(21))/2

Solve for x: log_{3}(x-1)+log_{3}(x+2)=1

The solution is x=(-1+sqrt(21))/2

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lo g_{3} (x - 1) + lo g_{3} (x + 2) = 1

x = \frac{- 1 + 21}{2}

Solution steps

lo g_{3} (x - 1) + lo g_{3} (x + 2) = 1

Apply log rules

(x - 1) (x + 2) = 3

Solve

(x - 1) (x + 2) = 3 : x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

Verify Solutions:

x = \frac{- 1 + 21}{2}

True

, x = \frac{- 1 - 21}{2}

False

The solution is

x = \frac{- 1 + 21}{2}

y, lo g_{b} (y) = x

lo g_{10} (3 a) = 0

ln (x) = - ln (x + 1)

lo g_{2} (5 x + 1) = 4

lo g_{2} (\frac{k + 2}{3 - k}) = - 2

What is the answer to log_{3}(x-1)+log_{3}(x+2)=1 ?
The answer to log_{3}(x-1)+log_{3}(x+2)=1 is x=(-1+sqrt(21))/2
Solve for x: log_{3}(x-1)+log_{3}(x+2)=1
The solution is x=(-1+sqrt(21))/2