What is the answer to 2.8=-log_{10}(x) ?

The answer to 2.8=-log_{10}(x) is x= 1/(10^{2.8)}

Solve for x: 2.8=-log_{10}(x)

The solution is x= 1/(10^{2.8)}

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2.8 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{2.8}}

Solution steps

2.8 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

2.8 + lo g_{10} (x) = 0

Move

2.8

to the right side

lo g_{10} (x) = - 2.8

Apply log rules

x = \frac{1}{1 0 ^{2.8}}

Verify Solutions:

x = \frac{1}{1 0 ^{2.8}}

True

The solution is

x = \frac{1}{1 0 ^{2.8}}

lo g_{3} (x + 7) + lo g_{3} (x + 5) = 1

lo g_{b} (8) = - \frac{1}{2}

1 + ln (3 x) = 0

lo g_{10} (x) = 0.17527

ln (7 x + 2) = 3

What is the answer to 2.8=-log_{10}(x) ?
The answer to 2.8=-log_{10}(x) is x= 1/(10^{2.8)}
Solve for x: 2.8=-log_{10}(x)
The solution is x= 1/(10^{2.8)}