What is the answer to log_{10}(3x)+log_{10}(9)=0 ?

The answer to log_{10}(3x)+log_{10}(9)=0 is x= 1/27

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log_{10}(3x)+log_{10}(9)=0

lo g_{10} (3 x) + lo g_{10} (9) = 0

x = \frac{1}{27}

Decimal Notation

x = 0.03703 \dots

Solution steps

lo g_{10} (3 x) + lo g_{10} (9) = 0

Move

lo g_{10} (9)

to the right side

lo g_{10} (3 x) = - lo g_{10} (9)

Apply log rules

3 x = \frac{1}{9}

Solve

3 x = \frac{1}{9} : x = \frac{1}{27}

x = \frac{1}{27}

Verify Solutions:

x = \frac{1}{27}

True

The solution is

x = \frac{1}{27}

lo g_{10} (x) - lo g_{10} (3) = 2

ln (x) = 42

ln (x) = 2 x

lo g_{5} (6 - 5 x) = 1 - x

ln (x) = 32

What is the answer to log_{10}(3x)+log_{10}(9)=0 ?
The answer to log_{10}(3x)+log_{10}(9)=0 is x= 1/27
Solve for x: log_{10}(3x)+log_{10}(9)=0
The solution is x= 1/27