What is the answer to log_{7}(X-2)+log_{7}(X+2)=1 ?

The answer to log_{7}(X-2)+log_{7}(X+2)=1 is X=sqrt(11)

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log_{7}(X-2)+log_{7}(X+2)=1

lo g_{7} (X - 2) + lo g_{7} (X + 2) = 1

X = 11

Decimal Notation

X = 3.31662 \dots

Solution steps

lo g_{7} (X - 2) + lo g_{7} (X + 2) = 1

Apply log rules

(X - 2) (X + 2) = 7

Solve

(X - 2) (X + 2) = 7 : X = 11, X = - 11

X = 11, X = - 11

Verify Solutions:

X = 11

True

, X = - 11

False

The solution is

X = 11

lo g_{10} (2 x + 5) = 1

ln (x^{3}) + ln (x) = 5

lo g_{5} (4 t + 7) - lo g_{5} (t) = 2

- lo g_{3} (x) + 2 = 0

10 = lo g_{2} (x)

What is the answer to log_{7}(X-2)+log_{7}(X+2)=1 ?
The answer to log_{7}(X-2)+log_{7}(X+2)=1 is X=sqrt(11)
Solve for X: log_{7}(X-2)+log_{7}(X+2)=1
The solution is X=sqrt(11)