What is the answer to log_{10}((4-2x)/(2x))=1 ?

The answer to log_{10}((4-2x)/(2x))=1 is x= 2/11

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log_{10}((4-2x)/(2x))=1

lo g_{10} (\frac{4 - 2 x}{2 x}) = 1

x = \frac{2}{11}

Decimal Notation

x = 0.18181 \dots

Solution steps

lo g_{10} (\frac{4 - 2 x}{2 x}) = 1

Apply log rules

\frac{4 - 2 x}{2 x} = 1 0^{1}

Multiply both sides by

2 x

\frac{4 - 2 x}{2 x} \cdot 2 x = 1 0^{1} \cdot 2 x

Simplify

4 - 2 x = 20 x

Solve

4 - 2 x = 20 x : x = \frac{2}{11}

x = \frac{2}{11}

Verify Solutions:

x = \frac{2}{11}

True

The solution is

x = \frac{2}{11}

lo g_{2} (3 x + 1) = 5

lo g_{10} (x^{2} - 1) = 0

lo g_{10} (x) = - 12.5

lo g_{3} (3 x - 6) = 2

- lo g_{10} (x) = 9.3

What is the answer to log_{10}((4-2x)/(2x))=1 ?
The answer to log_{10}((4-2x)/(2x))=1 is x= 2/11
Solve for x: log_{10}((4-2x)/(2x))=1
The solution is x= 2/11