What are the solutions to the equation -2=10x^2-21x ?

The solutions to the equation -2=10x^2-21x are x=2,x= 1/10

Find the zeros of -2=10x^2-21x

The zeros of -2=10x^2-21x are x=2,x= 1/10

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- 2 = 10 x^{2} - 21 x

x = 2, x = \frac{1}{10}

Decimal Notation

x = 2, x = 0.1

Solution steps

- 2 = 10 x^{2} - 21 x

Switch sides

10 x^{2} - 21 x = - 2

Move

2

to the left side

10 x^{2} - 21 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 10 \cdot 2}{2 \cdot 10}

(- 21)^{2} - 4 \cdot 10 \cdot 2 = 19

x_{1, 2} = \frac{- ( - 21 ) \pm 19}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 19}{2 \cdot 10}, x_{2} = \frac{- ( - 21 ) - 19}{2 \cdot 10}

x = \frac{- ( - 21 ) + 19}{2 \cdot 10} : 2

x = \frac{- ( - 21 ) - 19}{2 \cdot 10} : \frac{1}{10}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{10}

6 x - 4 (2 x + 8) = 16

5 x + 12 = x^{2}

6 x > 24

- 21 + 6 x \geq 3 (7 x + 4) - 4 x

\frac{1}{4} x + 8 \leq 12

What are the solutions to the equation -2=10x^2-21x ?
The solutions to the equation -2=10x^2-21x are x=2,x= 1/10
Find the zeros of -2=10x^2-21x
The zeros of -2=10x^2-21x are x=2,x= 1/10