What is the answer to x=10log_{10}(x) ?

The answer to x=10log_{10}(x) is x=10,x=-(10\W_{0}(-\frac{ln(10))/(10))}{ln(10)}

Solve for x: x=10log_{10}(x)

The solution is x=10,x=-(10\W_{0}(-\frac{ln(10))/(10))}{ln(10)}

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x = 10 lo g_{10} (x)

x = 10, x = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{10} )}{ln ( 10 )}

Solution steps

x = 10 lo g_{10} (x)

Switch sides

10 lo g_{10} (x) = x

Divide both sides by

10

lo g_{10} (x) = \frac{x}{10}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x)} = 1 0^{\frac{x}{10}}

Simplify

1 0^{l o g_{10} (x)} : x

x = 1 0^{\frac{x}{10}}

Solve

x = 1 0^{\frac{x}{10}} : x = 10, x = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{10} )}{ln ( 10 )}

x = 10, x = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{10} )}{ln ( 10 )}

Verify Solutions:

x = 10

True

, x = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{10} )}{ln ( 10 )}

True

The solutions are

x = 10, x = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{10} )}{ln ( 10 )}

lo g_{x} (- x + 6) = 2

- 2 = lo g_{10} (x)

lo g_{4} (y) = 2

lo g_{27} (x) = \frac{2}{3}

2.4 = lo g_{10} (x)

What is the answer to x=10log_{10}(x) ?
The answer to x=10log_{10}(x) is x=10,x=-(10\W_{0}(-\frac{ln(10))/(10))}{ln(10)}
Solve for x: x=10log_{10}(x)
The solution is x=10,x=-(10\W_{0}(-\frac{ln(10))/(10))}{ln(10)}