What is the answer to ln(x-2)-ln(2x^1)-3=0 ?

The answer to ln(x-2)-ln(2x^1)-3=0 is No Solution for x\in\mathbb{R}

Solve for x: ln(x-2)-ln(2x^1)-3=0

The solution is No Solution for x\in\mathbb{R}

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ln (x - 2) - ln (2 x^{1}) - 3 = 0

No Solution for x \in R

Solution steps

ln (x - 2) - ln (2 x^{1}) - 3 = 0

Add

ln (2 x^{1})

to both sides

ln (x - 2) - ln (2 x^{1}) - 3 + ln (2 x^{1}) = 0 + ln (2 x^{1})

Simplify

ln (x - 2) - 3 = ln (2 x^{1})

Apply log rules

x - 2 = 2 e^{3} x

Solve

x - 2 = 2 e^{3} x : x = \frac{2}{1 - 2 e ^{3}}

x = \frac{2}{1 - 2 e ^{3}}

Verify Solutions:

x = \frac{2}{1 - 2 e ^{3}}

False

The solution is

No Solution for x \in R

lo g_{5} (x^{2} + 49) = 2

- lo g_{10} (x) = 8.9

lo g_{5} (n) = 3

60 = 10 lo g_{10} (x)

2 lo g_{3} (x) = 4 + 6 lo g_{x} (3)

What is the answer to ln(x-2)-ln(2x^1)-3=0 ?
The answer to ln(x-2)-ln(2x^1)-3=0 is No Solution for x\in\mathbb{R}
Solve for x: ln(x-2)-ln(2x^1)-3=0
The solution is No Solution for x\in\mathbb{R}