What is the answer to ln(x)+ln(2x)=-3 ?

The answer to ln(x)+ln(2x)=-3 is x=e^{(-3-ln(2))/2}

Solve for x: ln(x)+ln(2x)=-3

The solution is x=e^{(-3-ln(2))/2}

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ln (x) + ln (2 x) = - 3

x = e^{\frac{- 3 - l n ( 2 )}{2}}

Solution steps

ln (x) + ln (2 x) = - 3

Apply log rules

x = e^{\frac{- 3 - l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{- 3 - l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{- 3 - l n ( 2 )}{2}}

lo g_{3} (p) = 7

lo g_{3} (2 x + 3) = 4 - lo g_{3} (x + 6)

lo g_{3} (2) + lo g_{3} (b + 1) = 1

3^{l o g_{x} (81)} = x

lo g_{x} (625) = - 4

What is the answer to ln(x)+ln(2x)=-3 ?
The answer to ln(x)+ln(2x)=-3 is x=e^{(-3-ln(2))/2}
Solve for x: ln(x)+ln(2x)=-3
The solution is x=e^{(-3-ln(2))/2}