What is the answer to log_{10}(γ)=0.16096 ?

The answer to log_{10}(γ)=0.16096 is γ=10^{0.16096}

Solve for γ: log_{10}(γ)=0.16096

The solution is γ=10^{0.16096}

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lo g_{10} (γ) = 0.16096

γ = 1 0^{0.16096}

Solution steps

lo g_{10} (γ) = 0.16096

Apply log rules

γ = 1 0^{0.16096}

- 3 lo g_{10} (- 37 x + 1) + 1 = - 8

ln (2) = ln (- 1 + c)

3 lo g_{5} (x) = lo g_{5} (x)

lo g_{10} (x) = - 1.34

4 ln (x + 2) = - 4

What is the answer to log_{10}(γ)=0.16096 ?
The answer to log_{10}(γ)=0.16096 is γ=10^{0.16096}
Solve for γ: log_{10}(γ)=0.16096
The solution is γ=10^{0.16096}