What is the answer to 2log_{3}(y-6)-log_{3}(y-4)=2 ?

The answer to 2log_{3}(y-6)-log_{3}(y-4)=2 is y=(21+3sqrt(17))/2

Solve for y: 2log_{3}(y-6)-log_{3}(y-4)=2

The solution is y=(21+3sqrt(17))/2

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2 lo g_{3} (y - 6) - lo g_{3} (y - 4) = 2

y = \frac{21 + 3 17}{2}

Solution steps

2 lo g_{3} (y - 6) - lo g_{3} (y - 4) = 2

Apply log rules

(y - 6)^{2} = 9 (y - 4)

Solve

(y - 6)^{2} = 9 (y - 4) : y = \frac{21 + 3 17}{2}, y = \frac{21 - 3 17}{2}

y = \frac{21 + 3 17}{2}, y = \frac{21 - 3 17}{2}

Verify Solutions:

y = \frac{21 + 3 17}{2}

True

, y = \frac{21 - 3 17}{2}

False

The solution is

y = \frac{21 + 3 17}{2}

5 ln (8 x - 4) + 5 = 25

lo g_{3} ((x + 3) (x - 5)) = 2

ln (x + 2) + ln (x) = 0

lo g_{2} (2 x) - 3 lo g_{2} (2) = 3

ln (x) = 2.85

What is the answer to 2log_{3}(y-6)-log_{3}(y-4)=2 ?
The answer to 2log_{3}(y-6)-log_{3}(y-4)=2 is y=(21+3sqrt(17))/2
Solve for y: 2log_{3}(y-6)-log_{3}(y-4)=2
The solution is y=(21+3sqrt(17))/2