What is the answer to log_{5}(x-3)+log_{5}(x+3)=2 ?

The answer to log_{5}(x-3)+log_{5}(x+3)=2 is x=sqrt(34)

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log_{5}(x-3)+log_{5}(x+3)=2

lo g_{5} (x - 3) + lo g_{5} (x + 3) = 2

x = 34

Solution steps

lo g_{5} (x - 3) + lo g_{5} (x + 3) = 2

Apply log rules

(x - 3) (x + 3) = 25

Solve

(x - 3) (x + 3) = 25 : x = 34, x = - 34

x = 34, x = - 34

Verify Solutions:

x = 34

True

, x = - 34

False

The solution is

x = 34

lo g_{81} (x) = - \frac{1}{4}

5 ln (4 x - 9) + 7 = - 8

ln (n^{2} + 2 n + 1) = 0

3 ln (2 x) = - 3

lo g_{16} (5 x - 2) = \frac{3}{4}

What is the answer to log_{5}(x-3)+log_{5}(x+3)=2 ?
The answer to log_{5}(x-3)+log_{5}(x+3)=2 is x=sqrt(34)
Solve for x: log_{5}(x-3)+log_{5}(x+3)=2
The solution is x=sqrt(34)