What is the answer to log_{2}(x)+log_{2}(x+3)=2 ?

The answer to log_{2}(x)+log_{2}(x+3)=2 is x=1

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log_{2}(x)+log_{2}(x+3)=2

lo g_{2} (x) + lo g_{2} (x + 3) = 2

x = 1

Solution steps

lo g_{2} (x) + lo g_{2} (x + 3) = 2

Apply log rules

x (x + 3) = 4

Solve

x (x + 3) = 4 : x = 1, x = - 4

x = 1, x = - 4

Verify Solutions:

x = 1

True

, x = - 4

False

The solution is

x = 1

lo g_{5} (a) = 3

lo g_{2} (x - 7) = 4 + lo g_{2} (x + 8)

x, z = ln (x + y)

lo g_{3} (x + 5) = 0

e x ln (x) = \frac{ln ( x )}{e x}

What is the answer to log_{2}(x)+log_{2}(x+3)=2 ?
The answer to log_{2}(x)+log_{2}(x+3)=2 is x=1
Solve for x: log_{2}(x)+log_{2}(x+3)=2
The solution is x=1