What is the answer to log_{10}(y+21)+log_{10}(y)=2 ?

The answer to log_{10}(y+21)+log_{10}(y)=2 is y=4

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log_{10}(y+21)+log_{10}(y)=2

lo g_{10} (y + 21) + lo g_{10} (y) = 2

y = 4

Solution steps

lo g_{10} (y + 21) + lo g_{10} (y) = 2

Apply log rules

(y + 21) y = 100

Solve

(y + 21) y = 100 : y = 4, y = - 25

y = 4, y = - 25

Verify Solutions:

y = 4

True

, y = - 25

False

The solution is

y = 4

ln ((x - 2)^{2}) = 12

lo g_{2} (x^{2} - 1) = lo g_{2} (8)

lo g_{x} (243) = 2.5

lo g_{6} (2 x) = 3

(ln (x))^{2} + 4 ln (x) + 4 = 0

What is the answer to log_{10}(y+21)+log_{10}(y)=2 ?
The answer to log_{10}(y+21)+log_{10}(y)=2 is y=4
Solve for y: log_{10}(y+21)+log_{10}(y)=2
The solution is y=4