What is the answer to log_{5}(x^2)=log_{5}(3x+4) ?

The answer to log_{5}(x^2)=log_{5}(3x+4) is x=4,x=-1

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log_{5}(x^2)=log_{5}(3x+4)

lo g_{5} (x^{2}) = lo g_{5} (3 x + 4)

x = 4, x = - 1

Solution steps

lo g_{5} (x^{2}) = lo g_{5} (3 x + 4)

Apply log rules

x^{2} = 3 x + 4

Solve

x^{2} = 3 x + 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

True

The solutions are

x = 4, x = - 1

3 - ln (x) = \frac{x}{e} + 1

lo g_{10} (x) = 2.6

1 = 10 lo g_{10} (\frac{x}{1})

lo g_{4} ((2 - 3 x)^{2}) = 1

lo g_{10} (p - 1) = n

What is the answer to log_{5}(x^2)=log_{5}(3x+4) ?
The answer to log_{5}(x^2)=log_{5}(3x+4) is x=4,x=-1
Solve for x: log_{5}(x^2)=log_{5}(3x+4)
The solution is x=4,x=-1