What is the answer to log_{7}(x+6)+log_{7}(x)=1 ?

The answer to log_{7}(x+6)+log_{7}(x)=1 is x=1

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log_{7}(x+6)+log_{7}(x)=1

lo g_{7} (x + 6) + lo g_{7} (x) = 1

x = 1

Solution steps

lo g_{7} (x + 6) + lo g_{7} (x) = 1

Apply log rules

(x + 6) x = 7

Solve

(x + 6) x = 7 : x = 1, x = - 7

x = 1, x = - 7

Verify Solutions:

x = 1

True

, x = - 7

False

The solution is

x = 1

lo g_{5} (3 x + 4) = 2

lo g_{10} (x) = 1.8

3 lo g_{10} (x) = - 3

lo g_{10} (x) = 107

ln (x - 4) = ln (x) - 4

What is the answer to log_{7}(x+6)+log_{7}(x)=1 ?
The answer to log_{7}(x+6)+log_{7}(x)=1 is x=1
Solve for x: log_{7}(x+6)+log_{7}(x)=1
The solution is x=1