What is the answer to 2log_{10}(x)+log_{10}(x-1)=2 ?

The answer to 2log_{10}(x)+log_{10}(x-1)=2 is x=5

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2log_{10}(x)+log_{10}(x-1)=2

2 lo g_{10} (x) + lo g_{10} (x - 1) = 2

x = 5

Solution steps

2 lo g_{10} (x) + lo g_{10} (x - 1) = 2

Apply log rules

x^{2} (x - 1) = 100

Solve

x^{2} (x - 1) = 100 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

0.209 = - lo g_{10} (x)

lo g_{4} (a) = lo g_{2} (x), a > 0

4 lo g_{10} (x + 3) = 9

- ln (x) = 1

6 ln (4 x - 4) - 5 = 37

What is the answer to 2log_{10}(x)+log_{10}(x-1)=2 ?
The answer to 2log_{10}(x)+log_{10}(x-1)=2 is x=5
Solve for x: 2log_{10}(x)+log_{10}(x-1)=2
The solution is x=5