What is the answer to log_{2}(4x-1)=3 ?

The answer to log_{2}(4x-1)=3 is x= 9/4

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log_{2}(4x-1)=3

lo g_{2} (4 x - 1) = 3

x = \frac{9}{4}

Decimal Notation

x = 2.25

Solution steps

lo g_{2} (4 x - 1) = 3

Apply log rules

4 x - 1 = 8

Solve

4 x - 1 = 8 : x = \frac{9}{4}

x = \frac{9}{4}

x, y = ln (x y)

ln (1 - 2 x) = 0.4

lo g_{10} (x^{3} + 2000) = 2

ln (x + 4) - ln (x - 6) = 1

lo g_{2} (x + 1) = 1 - lo g_{2} (x)