What is the answer to log_{5}(x+3)+log_{5}(x)=2 ?

The answer to log_{5}(x+3)+log_{5}(x)=2 is x=(-3+sqrt(109))/2

Solve for x: log_{5}(x+3)+log_{5}(x)=2

The solution is x=(-3+sqrt(109))/2

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lo g_{5} (x + 3) + lo g_{5} (x) = 2

x = \frac{- 3 + 109}{2}

Decimal Notation

x = 3.72015 \dots

Solution steps

lo g_{5} (x + 3) + lo g_{5} (x) = 2

Apply log rules

(x + 3) x = 25

Solve

(x + 3) x = 25 : x = \frac{- 3 + 109}{2}, x = \frac{- 3 - 109}{2}

x = \frac{- 3 + 109}{2}, x = \frac{- 3 - 109}{2}

Verify Solutions:

x = \frac{- 3 + 109}{2}

True

, x = \frac{- 3 - 109}{2}

False

The solution is

x = \frac{- 3 + 109}{2}

lo g_{25} (x) = \frac{- 1}{2}

lo g_{2} (\frac{x + 1}{x - 1}) = 2

lo g_{10} (3 x) = lo g_{10} (9)

ln (x) = 0.95 x + 0.01

lo g_{10} (2 x) + lo g_{10} (x - 5) = 2

What is the answer to log_{5}(x+3)+log_{5}(x)=2 ?
The answer to log_{5}(x+3)+log_{5}(x)=2 is x=(-3+sqrt(109))/2
Solve for x: log_{5}(x+3)+log_{5}(x)=2
The solution is x=(-3+sqrt(109))/2