What are the solutions to the equation (3x-2)^2=28 ?

The solutions to the equation (3x-2)^2=28 are x=(2sqrt(7)+2)/3 ,x=(-2sqrt(7)+2)/3

Find the zeros of (3x-2)^2=28

The zeros of (3x-2)^2=28 are x=(2sqrt(7)+2)/3 ,x=(-2sqrt(7)+2)/3

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(3 x - 2)^{2} = 28

x = \frac{2 7 + 2}{3}, x = \frac{- 2 7 + 2}{3}

Solution steps

(3 x - 2)^{2} = 28

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 2 = 28 : x = \frac{2 7 + 2}{3}

Solve

3 x - 2 = - 28 : x = \frac{- 2 7 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{2 7 + 2}{3}, x = \frac{- 2 7 + 2}{3}

6 + ∣ 3 x - 2 ∣ = 9

\frac{4 x + 23}{3} = 17

1 6^{\frac{- 7}{4}}

9 \cdot \frac{3}{5}

15 x^{2} + 29 x y - 14 y^{2}

What are the solutions to the equation (3x-2)^2=28 ?
The solutions to the equation (3x-2)^2=28 are x=(2sqrt(7)+2)/3 ,x=(-2sqrt(7)+2)/3
Find the zeros of (3x-2)^2=28
The zeros of (3x-2)^2=28 are x=(2sqrt(7)+2)/3 ,x=(-2sqrt(7)+2)/3