What is the answer to ln(x^2+x+10)=3 ?

The answer to ln(x^2+x+10)=3 is x=(-1+sqrt(4e^3-39))/2 ,x=(-1-sqrt(4e^3-39))/2

Solve for x: ln(x^2+x+10)=3

The solution is x=(-1+sqrt(4e^3-39))/2 ,x=(-1-sqrt(4e^3-39))/2

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ln (x^{2} + x + 10) = 3

x = \frac{- 1 + 4 e ^{3} - 39}{2}, x = \frac{- 1 - 4 e ^{3} - 39}{2}

Decimal Notation

x = 2.71489 \dots, x = - 3.71489 \dots

Solution steps

ln (x^{2} + x + 10) = 3

Apply log rules

x^{2} + x + 10 = e^{3}

Solve

x^{2} + x + 10 = e^{3} : x = \frac{- 1 + 4 e ^{3} - 39}{2}, x = \frac{- 1 - 4 e ^{3} - 39}{2}

x = \frac{- 1 + 4 e ^{3} - 39}{2}, x = \frac{- 1 - 4 e ^{3} - 39}{2}

3 = lo g_{y} (27)

ln (x + 9) + ln (x - 3) = 2 ln (x)

ln (e x) = 2

lo g_{\frac{1}{7}} (x) = - 2

lo g_{3} (x + 1) = 1

What is the answer to ln(x^2+x+10)=3 ?
The answer to ln(x^2+x+10)=3 is x=(-1+sqrt(4e^3-39))/2 ,x=(-1-sqrt(4e^3-39))/2
Solve for x: ln(x^2+x+10)=3
The solution is x=(-1+sqrt(4e^3-39))/2 ,x=(-1-sqrt(4e^3-39))/2