What is the answer to log_{x}(3-2x)=2 ?

The answer to log_{x}(3-2x)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{x}(3-2x)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{x} (3 - 2 x) = 2

No Solution for x \in R

Solution steps

lo g_{x} (3 - 2 x) = 2

Apply log rules

\frac{ln ( 3 - 2 x )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( 3 - 2 x )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (3 - 2 x) = 2 ln (x)

Apply log rules

3 - 2 x = x^{2}

Solve

3 - 2 x = x^{2} : x = 1, x = - 3

x = 1, x = - 3

Verify Solutions:

x = 1

False

, x = - 3

False

The solution is

No Solution for x \in R

lo g_{2} (5 x + 5) = 3

lo g_{3} (2 x + 7) = 2 + lo g_{3} (x)

(ln (x))^{4} - 3 (ln (x))^{2} - 4 = 0

40 = - 10 lo g_{10} ((1 - x)^{2})

lo g_{2} (x^{3} - 56) = 3

What is the answer to log_{x}(3-2x)=2 ?
The answer to log_{x}(3-2x)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{x}(3-2x)=2
The solution is No Solution for x\in\mathbb{R}