What is the answer to log_{16}(36)=1-log_{4}(x) ?

The answer to log_{16}(36)=1-log_{4}(x) is x= 2/3

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log_{16}(36)=1-log_{4}(x)

lo g_{16} (36) = 1 - lo g_{4} (x)

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

lo g_{16} (36) = 1 - lo g_{4} (x)

Move

lo g_{4} (x)

to the left side

lo g_{16} (36) + lo g_{4} (x) = 1

Move

lo g_{16} (36)

to the right side

lo g_{4} (x) = 1 - lo g_{16} (36)

Apply log rules

x = \frac{2}{3}

Verify Solutions:

x = \frac{2}{3}

True

The solution is

x = \frac{2}{3}

n - 8 lo g_{10} (n) = 0

x, lo g_{3} (x + 1) = 3

4 ln (- x) + 3 = 21

lo g_{2} (7 x + 11) = 5

lo g_{32} (x) = - \frac{3}{5}

What is the answer to log_{16}(36)=1-log_{4}(x) ?
The answer to log_{16}(36)=1-log_{4}(x) is x= 2/3
Solve for x: log_{16}(36)=1-log_{4}(x)
The solution is x= 2/3