What is the answer to ln(x^2+5x)=2ln(x+1) ?

The answer to ln(x^2+5x)=2ln(x+1) is x= 1/3

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ln(x^2+5x)=2ln(x+1)

ln (x^{2} + 5 x) = 2 ln (x + 1)

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

ln (x^{2} + 5 x) = 2 ln (x + 1)

Apply log rules

x^{2} + 5 x = (x + 1)^{2}

Solve

x^{2} + 5 x = (x + 1)^{2} : x = \frac{1}{3}

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

lo g_{6} (x) + lo g_{6} (3) = 2

lo g_{10} (z - 3) = 2

lo g_{10} ((x + 1)^{3}) = 2

lo g_{x} (\frac{1}{100}) = 2

lo g_{b} (16) = 2

What is the answer to ln(x^2+5x)=2ln(x+1) ?
The answer to ln(x^2+5x)=2ln(x+1) is x= 1/3
Solve for x: ln(x^2+5x)=2ln(x+1)
The solution is x= 1/3