What is the answer to solvefor u,log_{3}(3u)=t ?

The answer to solvefor u,log_{3}(3u)=t is u=3^{t-1}

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solvefor u,log_{3}(3u)=t

solve for

u, lo g_{3} (3 u) = t

u = 3^{t - 1}

Solution steps

lo g_{3} (3 u) = t

Apply log rules

3 u = 3^{t}

Solve

3 u = 3^{t} : u = 3^{t - 1}

u = 3^{t - 1}

lo g_{5} (2 x - 3) = 0

2 lo g_{10} (x) = lo g_{10} (4 x + 5)

lo g_{10} (x^{2} - 1) = 2

lo g_{10} (n) = 60000000

lo g_{a} (1296) = 4

What is the answer to solvefor u,log_{3}(3u)=t ?
The answer to solvefor u,log_{3}(3u)=t is u=3^{t-1}