What is the answer to -log_{10}(x)=12 ?

The answer to -log_{10}(x)=12 is x= 1/(10^{12)}

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-log_{10}(x)=12

- lo g_{10} (x) = 12

x = \frac{1}{1 0 ^{12}}

Decimal Notation

x = 1.0 E - 12

Solution steps

- lo g_{10} (x) = 12

Divide both sides by

- 1

lo g_{10} (x) = - 12

Apply log rules

x = \frac{1}{1 0 ^{12}}

Verify Solutions:

x = \frac{1}{1 0 ^{12}}

True

The solution is

x = \frac{1}{1 0 ^{12}}

lo g_{2} (x - 3) = 3 - lo g_{2} (x - 1)

ln (x + 5) + ln (x - 2) = 2 ln (x)

ln (x^{2}) = 2 ln (4) - ln (5)

lo g_{2} (x) = \frac{- 1}{2}

lo g_{2} (n) = 100

What is the answer to -log_{10}(x)=12 ?
The answer to -log_{10}(x)=12 is x= 1/(10^{12)}
Solve for x: -log_{10}(x)=12
The solution is x= 1/(10^{12)}