What is the answer to 1+log_{3}(x-1)=log_{3}(x+1) ?

The answer to 1+log_{3}(x-1)=log_{3}(x+1) is x=2

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1+log_{3}(x-1)=log_{3}(x+1)

1 + lo g_{3} (x - 1) = lo g_{3} (x + 1)

x = 2

Solution steps

1 + lo g_{3} (x - 1) = lo g_{3} (x + 1)

Apply log rules

3 (x - 1) = x + 1

Solve

3 (x - 1) = x + 1 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

2 lo g_{10} (x) - lo g_{10} (3) = 2

ln (x^{2}) = x

lo g_{3} (x) = lo g_{4} (x)

lo g_{\frac{2}{5}} (x) = - 1

ln (2 x - 3) = 5

What is the answer to 1+log_{3}(x-1)=log_{3}(x+1) ?
The answer to 1+log_{3}(x-1)=log_{3}(x+1) is x=2
Solve for x: 1+log_{3}(x-1)=log_{3}(x+1)
The solution is x=2