What is the answer to log_{10}(x)=2-log_{10}(x-15) ?

The answer to log_{10}(x)=2-log_{10}(x-15) is x=20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(x)=2-log_{10}(x-15)

lo g_{10} (x) = 2 - lo g_{10} (x - 15)

x = 20

Solution steps

lo g_{10} (x) = 2 - lo g_{10} (x - 15)

Add

lo g_{10} (x - 15)

to both sides

lo g_{10} (x) + lo g_{10} (x - 15) = 2 - lo g_{10} (x - 15) + lo g_{10} (x - 15)

Simplify

lo g_{10} (x) + lo g_{10} (x - 15) = 2

Apply log rules

x (x - 15) = 100

Solve

x (x - 15) = 100 : x = 20, x = - 5

x = 20, x = - 5

Verify Solutions:

x = 20

True

, x = - 5

False

The solution is

x = 20

x^{l o g_{3} (x)} = 81 x^{3}

lo g_{2} (27) = 3 lo g_{2} (x)

(ln (x))^{2} - ln (x^{7}) = 8

- lo g_{10} (10 x) = 11.45

2 lo g_{10} (x + 86) = 4

What is the answer to log_{10}(x)=2-log_{10}(x-15) ?
The answer to log_{10}(x)=2-log_{10}(x-15) is x=20
Solve for x: log_{10}(x)=2-log_{10}(x-15)
The solution is x=20